y'all think you hard?

damn, well i robbed a mom and pop store while high on sharpies



it's time for deep Fried TURKEY!!!

Christmas party in the house.

i know for a fact if i robbed a bank i wouldnt wtire it openly on the internet, you may be 'hard' but definately not smart


mCm

you can't be hard and smart at the same time. i said i was hard, bitch. i ain't hiding. i'll kill all the cops that come fo me when they read this post. that's cuz i'm hard, bitch. so, it follows that i am not smart.
Suppose G is a group of order pq where p is prime and p is greater than q. Then, by Cauchy's theorem, G has a subgroup of order p, namely (p). Let P=(p). P is the only subgroup of order p. Suppose otherwise, then there exists a subgroup A such that A^P=(e). The existence of such a group implies that there exist p^2 elements ap in G. But p^2>pq=|G| is a contradiction. Therefore, P is the only sugroup of order p in G. Consider the subgroup gPg^(-1) for g in G. It also has p elements. So, P is normal in G

fuk that shit, i'll kill all you muthapuckaz

yay...gotta love the diverse ns community

^and lots of sarcasm

that takes skill
binding destruction count: 3 so far this season, one pair of lines and two pairs of rossis: what will be next?

your cool man













shants; theyre not quite shorts, but not quite pants





**NWFT**

Yeah, seriously.

NS has become the official gathering of the world's dumbest people.



Scratch174, thank you.