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Posts: 1272

tan(e^x)-x = cos(e^y) differentiate implicitly. Not sure if I typed this in right to alpha wolfram http://www.wolframalpha.com/input/?i=implicit+derivative+of%3A+tan%28e%5Ex%29-x+%3D+cos%28e%5Ey%29. Any help would be greatly appreciated

Posts: 8185

Too high level of calc for my knowledge.

there are much better things to do with your life than spend it ruining others. -wh@t

Skiing is an art form, an escape from all things bad, skiing is perfect, skiing is my obsession.

Love is the amazing shivers you get when you're silently slipping through trees on a powder day, that overwhelming feeling of contentment where your heart beats a little faster and louder. That unmistakable grin of happiness that you can't shake off. It's unconditional, it's unbeatable, it's compassion and it's adventure.

Skiing is an art form, an escape from all things bad, skiing is perfect, skiing is my obsession.

Love is the amazing shivers you get when you're silently slipping through trees on a powder day, that overwhelming feeling of contentment where your heart beats a little faster and louder. That unmistakable grin of happiness that you can't shake off. It's unconditional, it's unbeatable, it's compassion and it's adventure.

Posts: 3216

i forget highschool calc

ski the east

i'm going to do this for the first time ever and not speak my mind.-- eheath on december 14th

march 2nd 2011 "this is a thread" fuck yea

Ellie Goulding ♥

i'm going to do this for the first time ever and not speak my mind.-- eheath on december 14th

march 2nd 2011 "this is a thread" fuck yea

Ellie Goulding ♥

Posts: 468

i believe its

e^x sec^2(e^x) - 1 = -e^y sin(e^y)

e^x sec^2(e^x) - 1 = -e^y sin(e^y)

Posts: 1272

this is what i got as well. The answer this sheet gives me is( -tan^2e^x)/(sine^y) hopefully it's wrong because i can't get it

Posts: 6041

hahah AP next wednesday.. i'm so fucked

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Posts: 1860

tan(e^x)-x = cos(e^y)

ok, so you would get.... e^xsec^2(e^x)-1 = e^y (dy/dx)(-sin(e^y))

and then solve for dy/dx:

(e^(x-y)sec^2(e^x)-1)/(-sin(e^y)) = dy/dx

anyone else get that? Im not sure if that's right

ok, so you would get.... e^xsec^2(e^x)-1 = e^y (dy/dx)(-sin(e^y))

and then solve for dy/dx:

(e^(x-y)sec^2(e^x)-1)/(-sin(e^y)) = dy/dx

anyone else get that? Im not sure if that's right

"ive been trying to fart for the past half hour"

--PatrickLennon

Yeah cool tricks!!!

--PatrickLennon

Yeah cool tricks!!!

Posts: 2377

same, i was in a calc class that I never did homework or studied in and still got and A. That being said most the people in my class got Cs

I was sad, I stopped being sad, and then I was awesome

Posts: 1860

you need a dy/dx since it's implicit

"ive been trying to fart for the past half hour"

--PatrickLennon

Yeah cool tricks!!!

--PatrickLennon

Yeah cool tricks!!!

Posts: 8185

Just kidding. It is differentiating shit from like calc 1. I completely forget how to do that. But you probably have to use trig differentiations and chain rule.

there are much better things to do with your life than spend it ruining others. -wh@t

Skiing is an art form, an escape from all things bad, skiing is perfect, skiing is my obsession.

Love is the amazing shivers you get when you're silently slipping through trees on a powder day, that overwhelming feeling of contentment where your heart beats a little faster and louder. That unmistakable grin of happiness that you can't shake off. It's unconditional, it's unbeatable, it's compassion and it's adventure.

Skiing is an art form, an escape from all things bad, skiing is perfect, skiing is my obsession.

Love is the amazing shivers you get when you're silently slipping through trees on a powder day, that overwhelming feeling of contentment where your heart beats a little faster and louder. That unmistakable grin of happiness that you can't shake off. It's unconditional, it's unbeatable, it's compassion and it's adventure.

Posts: 5226

Yeah ^ that seems about right, but you forgot the implicit part with dy/dx and stuff, but knowing what variable you're doing with this with respect to would help. I'd guess x, you the ys need to be dy/dx right? Haven't done one of those a while.

Calc related tangent (it's like a pun or something)

I'm deep into my power series homework problems, I did the ratio test for

∞

∑ ___[(-1)^n](x-1)^n __

n=1 (3^2n)(ln(n))

Wow that was hard to type. But did the ratio test for that and I forgot to write down the (x-1)^n and (x-1)^(n+1) terms in the absolute value ratio thing, finished, then realized that I forgot those. fuuuuuuuuuuuuuuuuuu

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Posts: 468

yup yup you're very right

Posts: 8776

(e^x)sec^2(e^x)-1=(e^y)dy/dx(-sin(e^y))

then solve for dy/dx

i think thats right, i could quite possibly be wrong though

then solve for dy/dx

i think thats right, i could quite possibly be wrong though

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Posts: 1679

ah fuck you just reminded me I got one next Thursday

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Posts: 1589

My brain is full of fuck!

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it is a weed to where they have some of the best skiing out there" - cyco250

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it is a weed to where they have some of the best skiing out there" - cyco250

my posts are worthless

Posts: 1860

yup that's what I got, but somehow it's supposed to be

( -tan^2e^x)/(sine^y).... I don't remember all my trig identities so I can't get any farther than solving for dy/dx with what you got.

( -tan^2e^x)/(sine^y).... I don't remember all my trig identities so I can't get any farther than solving for dy/dx with what you got.

"ive been trying to fart for the past half hour"

--PatrickLennon

Yeah cool tricks!!!

--PatrickLennon

Yeah cool tricks!!!

Posts: 1812

Ya your just not using your trig identities

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