A German V2 rocket from WW2 had a range of 300km, reaching a maximum height of 100km. What is the rocket's maximum initial velocity?

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Posts: 403

Cab anybody tell me how to solve this?

A German V2 rocket from WW2 had a range of 300km, reaching a maximum height of 100km. What is the rocket's maximum initial velocity?

Posts: 125

im sure you would need more information for that, like the time it takes to cover that distance so you can do speed=distance/time

Posts: 5452

Can't really answer this one with the information given.

You need to give flight time and some other info because a rocket unlike a bullet has a force on it the entire time and not just an initial launch force.

Also maximum initial velocity makes no sense because the initial velocity should be 0 because it is sitting on the ground and the maximum velocity would just be the next instant after the motor is lit...

You need to give flight time and some other info because a rocket unlike a bullet has a force on it the entire time and not just an initial launch force.

Also maximum initial velocity makes no sense because the initial velocity should be 0 because it is sitting on the ground and the maximum velocity would just be the next instant after the motor is lit...

Hickenlooper for Governor.

Posts: 1073

^You can answer it easily.

Equations of motion dude.

Posts: 5452

with a projectile ya, but not a powered rocket.

Hickenlooper for Governor.

Posts: 904

The rocket has travelled 150km at its max height of 100km. It vertical velocity component is equal to 0 at this point. solve for the initial velocity (y component) using, v^2=v(initial)^2 + 2(g)(y). With this value solve for the time of the whole trajectory. Then find out the initial x component. Add the x and y vectors together and solve the angle using tan(theta) = y component/ x component.

FLUNT

Posts: 1162

you use a system of equations and solve for vi which is v initial

1: dy=vi1/2T+1/2aT the first 1/2 T is because your using a height of 100 which is half way through the parabolic motion, a is gravity or 9.81

2.dx=viT there is no 1/2at^2 because a=0 in the x direction

now you simply solve this system for vi the t's should cancel out

Posts: 1073

I guess thats true, but obviously the prof is talking about a projectile situation here, so I'd say 4430 m/sec.

Posts: 403

We're treating the rocket as a projectile in this case.

Posts: 1162

^ nvm i like his better

Posts: 452

The answer is easy to find. use your equations hunter!!!!!

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Posts: 452

find the maximum height, then the time it takes to hit the ground, multiply that by 2 to find total time then multiply it by the x speed (horizontal). that should give you the total range.

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Posts: 403

haha thanks, +k for all

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newschoolrs is so epicwhenn you're drunk, i'll answer dis tomorrow !

cheers, luv u all !

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