**log**

*x*^3=(log*x)^3*

so there is three answers, one answer is 1.

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Posts: 1119

hey so i have a problem with my math homework in adv algebra 2. i need to answer this, if anyone could show me how to it wold be greatly apreciated, the problem is:

**log***x*^3=(log*x)^3*

so there is three answers, one answer is 1.

when you ride it out like a thug

Posts: 6076

ugh i hated logs, i did that last year in my second attempt at adv alg, but still dont understand.

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Posts: 249

another one would be -1, not so sure about the 3rd answer though, sry

I like to ski.

Posts: 1119

i know i hate them so much haha

when you ride it out like a thug

Posts: 1119

-1 doesnt work i dont think, sorry also i need to know HOW to do it.

when you ride it out like a thug

Posts: 10270

is the third answer (3)^(1/2) aka root 3?

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Posts: 4904

i did these last year, but cant remember them anymore. sorry, i'd help if i could

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Pros: super durable, new butter zone, symetric everything

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Posts: 1119

howd you get there? +k to everyone

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Posts: 3097

thats what i got.

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I'm Klaus Wolfenstein. Who are you?...nobody?...probably...

I'm Klaus Wolfenstein. Who are you?...nobody?...probably...

Posts: 7013

I'm assuming the question is:

log(x^3)=(logx)^3

It's all basic log rules

log(x^3) = logxlogxlogx

log(x^3) = log(3x)

x^3 = 3x

x(x^2 - 3) = 0

x = 0, sqrt(3)

log(x^3)=(logx)^3

It's all basic log rules

log(x^3) = logxlogxlogx

log(x^3) = log(3x)

x^3 = 3x

x(x^2 - 3) = 0

x = 0, sqrt(3)

"I'd marry skiing, but it's playing hard to get"

Posts: 1119

wait so what are the three answers? thank your my hero

when you ride it out like a thug

Posts: 9

Im not sure if Im getting the notation right but my answers were x=1,exp(sqrt(3)),exp(-sqrt(3))

log(x^3)=(logx)^3

3log(x)=log(x)^3

3log(x)-log(x)^3=0

let y=log(x)

3y-y^3=0

-y(y^2-3)=0

y=0,sqrt(3),-sqrt(3)

but then you have to sub back the y=log(x)

0=log(x) --> x=1

sqrt(3)=log(x) --> x=exp(sqrt(3))

-sqrt(3)=log(x) --> x=exp(-sqrt(3))

log(x^3)=(logx)^3

3log(x)=log(x)^3

3log(x)-log(x)^3=0

let y=log(x)

3y-y^3=0

-y(y^2-3)=0

y=0,sqrt(3),-sqrt(3)

but then you have to sub back the y=log(x)

0=log(x) --> x=1

sqrt(3)=log(x) --> x=exp(sqrt(3))

-sqrt(3)=log(x) --> x=exp(-sqrt(3))

Posts: 1119

whats exp mean haha

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Posts: 2

exp means exponential or in some cases e^(.....)

Posts: 1119

how do i put that in the calc to show my math teacher?

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Posts: 781

that hurts my eyes so much i almost cried

i never was good at math

i never was good at math

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Posts: 2163

he would be right if my mental math still works. everything looks good to me

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Posts: 1275

log(x)^3 = log(3x) by the rules of logarithms.

So, the original equation can be rewritten as

log(x^3) = log(3x)

Raise both sides to the base power, which eliminates the logs, leaving

x^3 = 3x

Subtract 3x

x^3 - 3x = 0

Factor out an x

x(x^2 - 3) = 0

The x term that was factored out gives an answer of 0, so you solve the remaining term

x^2 - 3 = 0 ----> x^2 = 3 ----> x = sqrt3

Keeping in mind that square roots give a positive and negative answer, your 3 solutions would be

x = 0

x = sqrt3

x = -sqrt3

So, the original equation can be rewritten as

log(x^3) = log(3x)

Raise both sides to the base power, which eliminates the logs, leaving

x^3 = 3x

Subtract 3x

x^3 - 3x = 0

Factor out an x

x(x^2 - 3) = 0

The x term that was factored out gives an answer of 0, so you solve the remaining term

x^2 - 3 = 0 ----> x^2 = 3 ----> x = sqrt3

Keeping in mind that square roots give a positive and negative answer, your 3 solutions would be

x = 0

x = sqrt3

x = -sqrt3

now you got me sittin here playin with my balls tryin to figure out what youre talking about. -swick825

Posts: 1275

This is wrong, as you already eliminated the log function, you don't need to add it back into the problem at the end. Additionally, the are logs with an unspecified base (assumed to be 10, I guess), but certainly not natural logs, so there wouldn't be an exponential function. e only arises from the ln function.

now you got me sittin here playin with my balls tryin to figure out what youre talking about. -swick825

Posts: 1771

sqrt3

it looks like squirt

i laughed

it looks like squirt

i laughed

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Posts: 9397

HALF OF YOU IN HERE ARE RETARDED

log(x^3) =\= log(3x)

log(x^3) = 3(logx)

STOP TRYING TO TEACH HIM IF YOU HAVE NO IDEA WHAT THE FUCK YOURE TALKING ABOUT

log(x^3) =\= log(3x)

log(x^3) = 3(logx)

STOP TRYING TO TEACH HIM IF YOU HAVE NO IDEA WHAT THE FUCK YOURE TALKING ABOUT

SEARCHBAR PLEASE

Posts: 9397

youre an idiot. what he is doing is subbing logx with Y. if y=something, then logx=something. you cant just get rid of a log completely. what he did is perfect

SEARCHBAR PLEASE

Posts: 9397

THIS ONE IS PERFECT. I AM ASIAN. I KNOW WHAT THE FUCK I AM TALKING ABOUT. I GOT AN 800 ON MY MATH SATS. MOST OF THESE PEOPLE ARE TELLING YOU THE WRONG THING. THIS ONE IS CORRECT

SEARCHBAR PLEASE

Posts: 99

Yea your right.. I just got done with logs

as he said you bring the Coefficient out to the front of the log, NOT in to the 3...

Posts: 9397

NO YOURE WRONG. LOG x^3 DOES NOT EQUAL LOG 3X. STOP FILLING HIS BRAIN WITH INCORRECT STUFF

SEARCHBAR PLEASE

Posts: 9397

YOURE TERRIBLE AT MATH JUST GTFOOOOOOOOOOOOO

SEARCHBAR PLEASE

Posts: 9397

NOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOO

asian gone crazy over math

asian gone crazy over math

SEARCHBAR PLEASE

Posts: 9397

NOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOO!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

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Posts: 939

mathematica that shit

Posts: 5702

i just started non-linear equations with word problmes (grade ten) and it blows...

i dont think that shtuff will ever make sense to me

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ski MSLM!

and horseshoe...

and blue.

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Posts: 317

haha my calc 2 class are all asians, indians or arab.

5 seconds ago is gone forever, you will never get it back. wtf

Posts: 10772

this thread just got taken over by asian mathlete. holy shit.

Posts: 1119

what is the answer in decimal form? the sqrt of 3?

when you ride it out like a thug

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