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Posts: 420

So I need some help with my math homework. I need to find the slope of the line tangent to the given point y=2x^2 at (-2,8) I know your supposed to find the derivative but I don't know what to so from there

Its not peer pressure... Its just your turn- Will

I'm a rookie currently cause I've never been here and i don't even know what i'm doing.- Nick Martini

Live your Life Love your Life No Regrets.. Live Learn and move forward positively- CR Johnson

I'm a rookie currently cause I've never been here and i don't even know what i'm doing.- Nick Martini

Live your Life Love your Life No Regrets.. Live Learn and move forward positively- CR Johnson

Posts: 5283

I just had to go find my algebraic calc, lol, and I don't understand your question,

Posts: 475

So using the power rule you find the derivative (which is its own function that describes the slope of the first function at any giver point. The derivative is 4x. Then you put The x value you want to find the slope of in for the derivative, and you get f'(-2)=-8.

Future Disc Golf Pro in training

Posts: 7175

http://www.khanacademy.org/math/calculus/differential-calculus/derivative_intro/v/calculus--derivatives-1--new-hd-version

(zach)

Posts: 470

No one cares!!

Noodlebopping 4 LIFE

Posts: 4320

You could always just skip the problem. Seeing as it's homework.

Joisey reppin' da 201

Posts: 420

I figured it out actually but now I can't remember how to find the critical point of a function

Its not peer pressure... Its just your turn- Will

I'm a rookie currently cause I've never been here and i don't even know what i'm doing.- Nick Martini

Live your Life Love your Life No Regrets.. Live Learn and move forward positively- CR Johnson

I'm a rookie currently cause I've never been here and i don't even know what i'm doing.- Nick Martini

Live your Life Love your Life No Regrets.. Live Learn and move forward positively- CR Johnson

Posts: 270

Yeah we just did this in Calc like a month ago, this guy's got it spot on.

Minnesota? Yeah, it's pretty much Canada.

Posts: 639

Critical point of a function is a maximum or minimum point or its graph, at this point the slope has to be zero. So you find the x value were the derivative = 0. f(x)= 2x^2, f'(x)=4x. so the critical point is at x = 0. Which makes sense because your function is just a parabola.

Posts: 319

if you can't figure out the slope of a line you're gonna have some troubles with the rest of life.

Posts: 479

it's a tangent line of an exponential equation/function... not a linear line, totally different bud.

But yeah, that guy a couple posts down is right. But if they're making you do the

f(x-a) - f(a)

--------------

f(a)

or whatever that equation is, then that's totally different. Let me know if thats what you're supposed to do and I can help. Just can't remember the exact equation

Posts: 1093

Yup

Posts: 1681

I dont think he'll be using that method to find the answer... i learned that in precal but skipped it in calc (which im assuming hes taking now)

“Don't take life seriously because you can't come out of it alive.”

Posts: 479

We had to do it in our calc class in the beginning, but then we were able to use the "short cut" way, so idk

Posts: 151

Lol I wish I could go back in time when calc was this easy.

Posts: 851

Bump so I dont have to make a new thread,

this projects due tomorrow and ive done math all day and im exhausted and cant get my mind to compute anymore can someone help me with this.

Write an equation (y = mx+b) for the graph of a linear function that:

has slope 5 and y-intercept -5

has slope -5/6 and y-intercept -6/5

has slope -5 and y-intercept 6

this projects due tomorrow and ive done math all day and im exhausted and cant get my mind to compute anymore can someone help me with this.

Write an equation (y = mx+b) for the graph of a linear function that:

has slope 5 and y-intercept -5

has slope -5/6 and y-intercept -6/5

has slope -5 and y-intercept 6

CALGARY

I don't even ski anymore i just lift

#DodgeCrew

You wanna break dance with my wiener? well that is a colossal task - Penguinz0

I don't even ski anymore i just lift

#DodgeCrew

You wanna break dance with my wiener? well that is a colossal task - Penguinz0

Posts: 3251

DaffyDaDakBump so I dont have to make a new thread,

this projects due tomorrow and ive done math all day and im exhausted and cant get my mind to compute anymore can someone help me with this.

Write an equation (y = mx+b) for the graph of a linear function that:

has slope 5 and y-intercept -5

has slope -5/6 and y-intercept -6/5

has slope -5 and y-intercept 6

m is the slope and b is the y intercept

oh to be in grade 9 again...

Posts: 437

DaffyDaDakBump so I dont have to make a new thread,

this projects due tomorrow and ive done math all day and im exhausted and cant get my mind to compute anymore can someone help me with this.

Write an equation (y = mx+b) for the graph of a linear function that:

has slope 5 and y-intercept -5

has slope -5/6 and y-intercept -6/5

has slope -5 and y-intercept 6

erikKm is the slope and b is the y intercept

oh to be in grade 9 again...

A.k.a...

y=5x-5

y=-5/6x-6/5

y=-5x+6

watch your profanity

Posts: 851

erikKm is the slope and b is the y intercept

oh to be in grade 9 again...

itzkiA.k.a...

y=5x-5

y=-5/6x-6/5

y=-5x+6

grade 11 actually haha.... i got another one for you guys

For the function f(x) = -3x + 8, determine f(-2).

CALGARY

I don't even ski anymore i just lift

#DodgeCrew

You wanna break dance with my wiener? well that is a colossal task - Penguinz0

I don't even ski anymore i just lift

#DodgeCrew

You wanna break dance with my wiener? well that is a colossal task - Penguinz0

Posts: 851

DaffyDaDakgrade 11 actually haha.... i got another one for you guys

For the function f(x) = -3x + 8, determine f(-2).

pretty sure its 2

CALGARY

I don't even ski anymore i just lift

#DodgeCrew

You wanna break dance with my wiener? well that is a colossal task - Penguinz0

I don't even ski anymore i just lift

#DodgeCrew

You wanna break dance with my wiener? well that is a colossal task - Penguinz0

Posts: 320

DaffyDaDakpretty sure its 2

It's not. Since f(x) means you put whatever number you have as "x" in the equation, -2 is taking the place of x in the equation. You take -3(-2) + 8 which gives you an answer of 14.

I love me a good pancake.

"She got a big booty so I call her big booty"- 2 Chainz

"She got a big booty so I call her big booty"- 2 Chainz

Posts: 85

Step 1. Use power rule to find derivative of the function 2x^2:

Constant 2 times n (in x^n) times x^(n-1), or x^1, or x

fprime= 4x

Step 2. Plug in x value -2 to find the derivative at that point.

fprime(-2)=4(-2)

fprime(-2)= -8

Step 3. Pee in her butt

Step 4. Slope of the tangent line at (-2, 8)= fprime(-2)= -8

Step 5. Find tangent line using point slope form

y= -8(x+2)+8

Constant 2 times n (in x^n) times x^(n-1), or x^1, or x

fprime= 4x

Step 2. Plug in x value -2 to find the derivative at that point.

fprime(-2)=4(-2)

fprime(-2)= -8

Step 3. Pee in her butt

Step 4. Slope of the tangent line at (-2, 8)= fprime(-2)= -8

Step 5. Find tangent line using point slope form

y= -8(x+2)+8

Posts: 2821

erikKm is the slope and b is the y intercept

oh to be in grade 9 again...

you mean grade 6

Hood crew fucked yo bitch

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