Two objects with masses 4.00kg and 1.80kg hang 0.500m above the floor from the ends of a cord 7.30m long passing over a frictionless pulley. Both objects start from rest.
what is the maximum height reached by the 1.8kg block?
ok so isn't it just that the 4.0 kg block will obviously go down until it hits the floor, which is 0.5 m away? well if they are connected by a pully, then that should pull the 1.8 kg up .5m, making its final (and highest height) 1m
i hate online homework soooo damn much. At first i thought it would be super convenient, but i have never been so close to breaking my computer. There super picky about there answers and it so easy to make a insignificant mistake. Plus my dorm doesnt have wifi so i have to sit at my desk for fucking hours everyday
Sometimes i think that my life is a dream,, and i wonder whose it is,, and if they're enjoying it..
I meant just the implants, not on me. Just like pillows. -arabian.
to get in the position to lie you need to do lots of eye fucking.-LordoftheTrees
have sexual intercourse with females, inherit some sort of profit. -Big_Spence
being a girl is nice for masturbation purposes...and you get to play with your own tittehz...but you do have to squeeze 6-8 pound living creatures out of your vagina...you got that to look forward to. -Gator.
mastering physics!!! I hate that so much! my uni loves it and all the students hate it... it takes so long to input answers and they are nearly always wrongly formatted,....
RIP Shane Mcconkey
"love tha floaty fluff and i hate knob head lift peeps who say that yo planks aint gonna fit on the racks on them poma gondalas - mate, they're my skis bitch i know if fitage is gonna be ish". - my Bro
my mashups ❶ http://www.facebook.com/pages/gottamashemall/111794092171804
NEW album download here ❷ http://www.mediafire.com/?ygglzmdzjom
Yeah I got 1.20753 using g= 10m/s^2. Basically find the acceleration upwards by taking the difference of the tension in the string(from the other mass) and the force of gravity. Then find the time it takes for the mass to fall(or the other mass to reach 1m). Find the velocity of the 1.8 kg ball at this point( this is vo for the next equation). From then on the 1.8 kg mass is a projectile. Find the equation for y. To find the time until it reaches its peak I derived this and solved for dy/dt=0. Take this time and plug it into your equation for y. Easy... haha not really.
ma = T - mg
y = 0 + 0 + 1/2*(a)*t^2
v = vo + at
y = yo + vo*t - 1/2*(g)*t^2
y = 1.20753 m.