lim_________

__3x^2 - 5x^3 + 4__

x -> (infinity) 3x^2 + 5x - 2

whats the limit?!?!

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Posts: 1872

i have a problem and have no idea how to do it. I NEED FAST!!

lim___________3x^2 - 5x^3 + 4__

x -> (infinity) 3x^2 + 5x - 2

whats the limit?!?!

lim_________

x -> (infinity) 3x^2 + 5x - 2

whats the limit?!?!

Posts: 25875

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"I resigned from work fifty years ago! And what did I do besides read and write? Climb mountains, ski and make love to a wonderful woman..."

Posts: 4545

I used to know that stuff. Wow, I forgot a LOT over the summer.

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Posts: 52263

lim_________3x^2 - 5x^3 + 4

x -> (infinity) 3x^2 + 5x - 2

so its infinity - infinity + 4 over infinity + infinity - 2

so

4

inifinty-2

And then that means something, i can remember exactly but a number over infinity is basically to 0? hope that helps.

x -> (infinity) 3x^2 + 5x - 2

so its infinity - infinity + 4 over infinity + infinity - 2

so

4

inifinty-2

And then that means something, i can remember exactly but a number over infinity is basically to 0? hope that helps.

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Posts: 1872

2389rq3rjowr

Posts: 424

okay, i dont think any ones right so far. sorry eheath.

lim x-> infinity for (3x^2 - 5x^3 + 4)/(3x^2 + 5x - 2)

when you plug infinty in for x you get infinity over infinity, and that cant be the answer. so you have to the the derivative of the top and the bottom.

It will be lim as x -> infinty for(6x - 15x^2)/(6x + 5)

this will also be infinity over infinity so you have to take the derivative again.

lim as x-> infinity for (6 - 30x)/(6)

okay, now when you plug infinity into this you get (6 - 30(infinity))/(6), so the answer is **n****egative infinity.** I'm pretty sure thats right and hopefully that makes sense.

Posts: 52263

Ah yes, simplify of course. that all sounds much better.

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Posts: 6459

I concur.

_______________________________t_rob_________________

Posts: 1771

wow im dumb

THC:

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Posts: 1872

this sounds better... but yea.. how would you do it without taking the derivatives?

Posts: 2030

I just finished calculas finally. Therefor im done, and not gunna grab my notes to try and find the limits of this equation. Have fun with Crackulus.

Posts: 424

um... i dont think you can. They're easy derivatives though, i didnt use a calculator for any of that problem

Posts: 917

I see

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Posts: 85

i start calc in four days. this thread just makes me even more depressed about it. thanks guys....

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Posts: 2030

i was taught that infinity over infinity would just be equal to 1. I could be wrong though, i sleep alot.

Posts: 2030

or no its infinity haha fml

Posts: 335

same here.

i hate when shit like that happens and i can't remember things i used to be good at. it's always such a downer for myself

^i guess i'm just expecting too much of myself sometimes...

i hate when shit like that happens and i can't remember things i used to be good at. it's always such a downer for myself

^i guess i'm just expecting too much of myself sometimes...

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Posts: 955

Gotta differentiate everything a couple times, leaving you with -30x+6/6 (as mentioned before).

So yes, the answer is negative infinity.

So yes, the answer is negative infinity.

Posts: 335

k now i'm rememebering after looking at it for a while.

i'm sry to be a nerd, but here are some tips for having to evaluate limits going to infiinty.

compare the highest degree of the funtion. that's the biggest exponent of the variable. in this case it's 3. so, u basically ignore all numbers and variables with an exponent less than that highest degree. now there are only 3 possibilites:

1) if there's a variable with the highest degree on the top and bottom of the function, then your limit is always just the coefficents divided by themselves. (watch out for signs!)

2) if only the variable on top of the function has this highest degree, then it's either negative or positive infinity. again, depending on the sign.

3) if the variable on the bottom has the highest degree of the funtion, the limit is undefined since u can't divide by negative or positive infinty.

hope this made sense. this way i used to be able to rush through the calc homework when we had to evaluate limits at infinity.

i'm sry to be a nerd, but here are some tips for having to evaluate limits going to infiinty.

compare the highest degree of the funtion. that's the biggest exponent of the variable. in this case it's 3. so, u basically ignore all numbers and variables with an exponent less than that highest degree. now there are only 3 possibilites:

1) if there's a variable with the highest degree on the top and bottom of the function, then your limit is always just the coefficents divided by themselves. (watch out for signs!)

2) if only the variable on top of the function has this highest degree, then it's either negative or positive infinity. again, depending on the sign.

3) if the variable on the bottom has the highest degree of the funtion, the limit is undefined since u can't divide by negative or positive infinty.

hope this made sense. this way i used to be able to rush through the calc homework when we had to evaluate limits at infinity.

"Chill your tits"

-PlasticVagina.

"i was liek wtf lilly u whore im a human and we dont deal with that kinda pussy"

-Prosnurfer.

-PlasticVagina.

"i was liek wtf lilly u whore im a human and we dont deal with that kinda pussy"

-Prosnurfer.

Posts: 902

for future reference when finding a limit when x goes to +/- infinity just divide my the highest degree in the denominator

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Posts: 335

sry for triple post but so in this case you would just look at -5x^3 and see the negative and since -5x^3 is at the top, you know it's negatvie infinity.

problem solved within 5 seconds. :)

i really hope this makes sense to you.

problem solved within 5 seconds. :)

i really hope this makes sense to you.

"Chill your tits"

-PlasticVagina.

"i was liek wtf lilly u whore im a human and we dont deal with that kinda pussy"

-Prosnurfer.

-PlasticVagina.

"i was liek wtf lilly u whore im a human and we dont deal with that kinda pussy"

-Prosnurfer.

Posts: 5264

my motivation for finishing calc is getting a tattoo.

as soon as I finish lin dif alg, im getting a tattoo of my favorite formula to show how bad ass of a nerd I am

as soon as I finish lin dif alg, im getting a tattoo of my favorite formula to show how bad ass of a nerd I am

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Posts: 1872

i got the answer.

so you multiply through by 1/x^2 over 1/x^2

then everythign with x under it becomes 0

so you get -5(x)/3 so when u plug in negative infinity it would become positive leaving you with**positive infinity **

so you multiply through by 1/x^2 over 1/x^2

then everythign with x under it becomes 0

so you get -5(x)/3 so when u plug in negative infinity it would become positive leaving you with

Posts: 335

that's right but dont u have to find the limit when x approaches (postive) infinty.

^ looking at your original post.

but, please do yourself a favor and reaad through my posts. if you get what i'm saying, you will solve problems like these within 5 seconds. no, not kidding.

^ looking at your original post.

but, please do yourself a favor and reaad through my posts. if you get what i'm saying, you will solve problems like these within 5 seconds. no, not kidding.

-PlasticVagina.

"i was liek wtf lilly u whore im a human and we dont deal with that kinda pussy"

-Prosnurfer.

Posts: 4087

Posts: 396

wow ap calc is gunna kick my ass

Posts: 1158

just started calc on tuesday. it looks weird lookin at math problems on newschoolers though haha

take me away.. to january..

Posts: 1872

yea i did. thanks man.

i just talked to my dad whos a math teacher and his exact words were

"the only thing that matters are the x in the numerator with the highest degree and the x in the denominator with the highest degree and take everything else away, and then from there plug in and all that matters from now on are the signs of the constant.

i just talked to my dad whos a math teacher and his exact words were

"the only thing that matters are the x in the numerator with the highest degree and the x in the denominator with the highest degree and take everything else away, and then from there plug in and all that matters from now on are the signs of the constant.

Posts: 335

yeah i'm glad it made sense.

exactly, that's how i learned it. now it's incredibly easy to take limiits approaching infinity.

:)

i would say /thread

exactly, that's how i learned it. now it's incredibly easy to take limiits approaching infinity.

:)

i would say /thread

-PlasticVagina.

"i was liek wtf lilly u whore im a human and we dont deal with that kinda pussy"

-Prosnurfer.

Posts: 2514

power of x is greater on top so that will dominate the bottom. since its -x^3 its infinity. if the power on the bottom is bigger it goes to zero. if they are the same power it goes to the leading coeffecients (2x/x) goes to 2 as x goes to infinity.

vote democrat, its easier than working

You are the worst member of Newschoolers.com currently. Congratulations. - Kepler

You are the worst member of Newschoolers.com currently. Congratulations. - Kepler

Posts: 2514

TAKE IT TO THE CALCULUS CULT!

vote democrat, its easier than working

You are the worst member of Newschoolers.com currently. Congratulations. - Kepler

You are the worst member of Newschoolers.com currently. Congratulations. - Kepler

Posts: 317

wow i really forgot a lot over the summer

5 seconds ago is gone forever, you will never get it back. wtf

Posts: 2549

This is right.

Posts: 905

shit FML im not even gonna step into that course

Letum Know

Posts: 2514

calc 1 is easy bones

vote democrat, its easier than working

You are the worst member of Newschoolers.com currently. Congratulations. - Kepler

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Posts: 1179

no dude its not that hard all once you see that the 3x^2 cancels, you just look to see what dominates as x goes to infinity

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