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PHYSICS HELP!

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Alpine3
Posts: 1811 - Karma: 24
i have a question that i cannot solve.... and need some help...

a steel ramp is to be built for sliding blocks of ice from a refrigeration plant down to ground level. if coefficient of friction =.05, find the angle with the horizontal at which the ice will slide at constant velocity.

anyone have any ideas?
Jan 9 2008 6:34PM
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Elijah.
Posts: 9322 - Karma: 76
Use the mass of the ice to figure out when Mu (Coeff. of friction) allows it go at a constant velocity.
Jan 9 2008 6:36PM
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freestyler540
Posts: 13046 - Karma: 18,292
The trick is to solve on a plain X axis. On this new axis, the force down the slope is: height x sin (theta)*angle of slope, this times the coefficient factor will give you the force down the slope, from that find the speed


Jan 9 2008 6:37PM
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GatoGordo
Posts: 1496 - Karma: 10
The ice will slide at a constant velocity if theta is 0. Just use that.
Jan 9 2008 7:01PM
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MCIRONCOCK
Posts: 3094 - Karma: 30
I have my physics mid-term tomorrow. I can't wait, it's gonna be a super fun 2 hour, 200 question test.
Jan 9 2008 7:04PM
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Pippin
Posts: 4846 - Karma: 661
don't hate on physics to much theres some really interesting parts in it, just stick it out and you'll see...
Jan 9 2008 7:07PM
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Tom.
Posts: 1954 - Karma: 12
Ff=µ*Fn
F=M*A

Ff=Fg
Fg=9.8*cos(θ)*M
Ff=.05*Fn
Fn=9.8*sin(θ)*M

9.8*cos(θ)*M=.05*9.8*sin(θ)*M
9.8*cos(θ)=.05*9.8*sin(θ)
9.8/(.05*9.8)=sin(θ)/cos(θ)=tan(θ)
arctan(1/.05)=θ

θ≈1.521

YAY, PHYSICS!!!
Jan 9 2008 7:23PM
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Pippin
Posts: 4846 - Karma: 661
^ arctan? is that like inverse?
Jan 9 2008 7:29PM
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Tom.
Posts: 1954 - Karma: 12
sorry I messed that one up. I was thinking that θ was with respect to the horizontal, also that was radians, so...


Ff=µ*Fn
F=M*A

Ff=Fg
Fg=9.8*sin(θ)*M
Ff=.05*Fn
Fn=9.8*cos(θ)*M

9.8*sin(θ)*M=.05*9.8*cos(θ)*M
9.8*sin(θ)=.05*9.8*cos(θ)
(.05*9.8)/9.8=sin(θ)/cos(θ)=tan(θ)
arctan(.05)=θ

θ≈2.862º or 0.050 radians.

Jan 9 2008 7:30PM
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Tom.
Posts: 1954 - Karma: 12
yeah its the same thing.

arctan = inverse tan = tan^-1
Jan 9 2008 7:32PM
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Tom.
Posts: 1954 - Karma: 12
Vertical******

quad post =\


Jan 9 2008 7:33PM
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