This is for a quiz if anybody could factor this that would be a great help. Thanks! +kkkk

Factor (x-5)(x^2+x+2)

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Posts: 2053

This is for a quiz if anybody could factor this that would be a great help. Thanks! +kkkk

Factor (x-5)(x^2+x+2)

Factor (x-5)(x^2+x+2)

Posts: 653

I hate my math addiction, yeah here one sec

Posts: 2482

The first term is already factored so you could just factor an x out of the 2nd part which would give youe x(x-5)(x+2)

Posts: 2053

Thanks man

Posts: 653

It's a non real answer, want an explanation?

Posts: 2482

wait fuck me i thought it was (x^2+2x) forget what i said you can't factor an x out because theres a 2 in there

Posts: 3866

i got x^3-4x^2-3x-10

i think that's right...

Posts: 2394

wolframalpha.com

Posts: 3866

oh wait that's mulitplying it out nevermind

Posts: 753

-10 + -3x + -4x2 + x3

Posts: 2053

Thanks everyone figured it out like

Posts: 4285

this thread is full of fail.

and that kid is right you can't factor it. if you plug it into a calculator, there is only one root, so you can't possibly factor it more. I tried reducing by using 5 as a root and came out with an imaginary number.

Unfortunately there are no asians on ns.

Posts: 2482

He said factor, not multiply them together.

If your looking for answers, depending on the context of the question, you could solve (x-5) and (x^2+2+2) separately for 0 which would give you 5 and a nonreal answer since you get 1 +- root(1-8) / 2

So it would be 1+-i(7^1/2)/2

Posts: 2482

I used the quadratic equation in case you were wondering. And if you don't know i = square root of -1 which is an imaginary number

Posts: 10639

im asain ;)

Posts: 4285

can you please inform me of how you factored it?

Posts: 2065

this reminded me why I have a D in math.

Posts: 3866

herrr derrr look what i posted after

Posts: 2482

ya its cool i fucked up at first too!

Posts: 8653

Ok wouldn't the first half be x=5 and then you would plug in the x^2+x+2 into the quadratic formula , then set those factors equal to zero and solve. Then check for extraneous roots? That's how we do it at school I think.

Posts: 2482

Ya and that gives you 1+- i(7^1/2) / 2

Posts: 647

The first term would make x=-5, and the other one you have to use the quadratic formula to figure it out, which then would be your second term, and if you completely simplified it, it would be an imaginary number. but if you haven't learned about them yet, I would just write it out like I have it (while taking into account that I'm typing it out, so it looks a little weird haha)

x= 5, (-1±√(-7))/2

x= 5, (-1±√(-7))/2

Posts: 8653

Oh, I didn't even realize you did it already! Thanks :)

Posts: 647

5, not -5

Posts: 2856

You gotta plug that shit into the quadratic. Google it and do it yourself

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