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Posts: 879

I have a test tommorow for Trigonometry and I'm very behind. I just don't get how

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Posts: 5591

If i remember correctly cosecant (csc) is the inverse of tangent (tan).

maybe that helps...?

maybe that helps...?

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Posts: 3747

no cotangent is inverse tangent

csc is inverse sine

that may help..? idk how to do the problem sry

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Posts: 8706

No csc(r/y) is the inverse of sin(y/r) and cos(x/r)

they give you 11/8 so the hypotenuse of the triangle is 11 and the y leg of the triangle is 8, find the x leg and plug it into the sign formula, put that into your calc, find the angle that is in the 2nd quadrant(90degrees-180degrees) and you are good to go.

hope that made sense

they give you 11/8 so the hypotenuse of the triangle is 11 and the y leg of the triangle is 8, find the x leg and plug it into the sign formula, put that into your calc, find the angle that is in the 2nd quadrant(90degrees-180degrees) and you are good to go.

hope that made sense

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Posts: 1861

so you would get whatever cos^-1(sqrroot:57) would be for the answer to #7... make sure your calc is in radians. Dont forget that the angle is between pi/2 and pi.

For #5: Circumference is 2(pi)(radius) or pi(diameter). Area is pi(radius^2). isolate r in the area equation, so r = sqrroot:(area/pi). Now that you know what r equals, plug that in to the circumference equation, so you get: C = 2(pi)(sqrroot:(area/pi)).

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Posts: 879

Okay i get that and it helped but when you get a problem like sin(cos^-1(-3/8))...How can you tell what quadrant it is in?

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"So many people live within unhappy circumstances and yet will not take the initiative to change their situation because they are conditioned to a life of security, conformity, and conservatism." - Christopher McCandless

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Posts: 1861

^ I always make the angle positive (not always required). If it isnt, add 2pi to the angle (in radians). make sure the number is in Quad 2 by being sure that the angle is between pi/2 (somewhere around 1.57) and pi (3.14...). if it isnt, subtract the angle from pi (to see the angle's proximity to the x-axis), then add that difference back to pi (to match that proximity, but on the other side of the x-axis).

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Posts: 1861

for 6b, you would are tryin to find angles where tan x = the angle where the tangent = x. lets try 0: tan 0=0 (0/1) and tan-1 (0) = 0 (at angle 0, the tangent = 0). This is not true for angle pi, because tan pi = 0. however, tan^-1 pi does not equal 0.

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Posts: 1165

lots of math help:

http://www.khanacademy.org/

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Posts: 24117

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Posts: 1861

^oh and make sure you make the answer 0+2(pi)k so the answer is applicable to an infinite domain.

for 6a, since we know that the tangent inverse of a number is equal to the angle where its tangent equals the number in the inverse (tan^-1(y)= x, tan x= y), x is an angle, and y is its tangent value. So the inverse of the tangent value of x will equal x. Because this equation is valid for all real numbers x (except at pi/2 and 3pi/2, because then tanx would be undefined), x belongs to the set of all real numbers. so you could say x does not equal (pi/2) + pi(k), so that the answer is applicable to an infinite domain.Hopefully that made sense.....

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Posts: 682

Here are a few things that will help you out

Sin = (1/Csc)

Csc = (1/Sin)

Cos = (1/Sec)

Sec = (1/Cos)

Tan = (1/Cot)

Cot = (1/Tan)

Pi = 180 Degrees

(Pi / 2) = 90 Degrees

Sin is positive in the 1st and 2nd quadrents, therefore, Csc is positive in the 1st and 2nd quadrents

Oh and that "O" the line through it is the greek letter theta, which is just a variable, like x or y

That should help

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Posts: 2553

In quadrant 1 all functions are +, in 2 sin and csc are +, in 3 tan and cot are +, in 4 cos and sec are +

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Posts: 3668

so glad i dropped my math course

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Posts: 879

whats the difference between Tan (Capital T) and tan??

bhodhisattva

"So many people live within unhappy circumstances and yet will not take the initiative to change their situation because they are conditioned to a life of security, conformity, and conservatism." - Christopher McCandless

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Posts: 1861

nothing.....at least i never heard of there being any difference.......

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Posts: 1477

Question 5 im not sure i understand or Question 6 since those are very specific rules for Tangent.

Question 6 is very simple though. co-secant is the reciprocal of sin (1/sin)

Therefore

csc (11/8) is the equivalent of 1/(11/8) or 8/11

now, sin^2+cos^2=1, That is a rule of trig

so

1-(11/8) gives you: -3/8

sqare root of that

there is your answer

*I think.

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Posts: 1861

I'm pretty sure you have to realize that csc x = radius/y and csc = hypotenuse/leg. So that means that the hypotenuse is 11, and one leg (y) is 8. Using the pythagorean theorem, the other leg is found to be sqrroot:57, that is, the x value is sqrroot:57. so now, if you have cos x (which equals x-value/hypotenuse) then the answer will be cos x = (sqrroot:57)/11.

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Posts: 437

C=2 x pi x r

A=pi x r x r

r= A/ (pi x r)

C= 2 x pi x A/(pi x r)

C=2A/r

r x r=A/pi

r = + or - sqroot(A/pi)

C= 2 x pi x A(pi x sqroot(A/pi))

Did I confuse you?

Posts: 8706

Circumference = 2πRadius

Area = π(Radius)^2

Radius = Area/(π x Radius)

Circumference = 2 x π x Area/(π x radius)

Circumference = 2 x Area / π

Radius x Radius = Area/π

Radius = +/- sqroot(Area/π)

Circumference = 2 x π x Area(π x sqroot(Area /π ))

Heres what this moron was getting at.

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Posts: 1855

Fuck. I have Trig next semester. I'm fucked...

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Posts: 24117

i actually found trig very straightforward and i suck at math

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Posts: 879

It's pretty easy if you somewhat pay attention. I mean i just don't pay attention at all in class and copy the homework off the answer key. It's hard to get a subject if you've never leanred it

bhodhisattva

"So many people live within unhappy circumstances and yet will not take the initiative to change their situation because they are conditioned to a life of security, conformity, and conservatism." - Christopher McCandless

"So many people live within unhappy circumstances and yet will not take the initiative to change their situation because they are conditioned to a life of security, conformity, and conservatism." - Christopher McCandless

Posts: 24117

thats exactly how i was in precalc last year. she never checked homework so i never did it and she was a terrible teacher so i failed every test

i only did well in the trig section because i'd learned it in A2

conic sections, trig functions, law of sines, all of that shit is actually pretty fun EXCEPT for fucking proofs with the identities

i only did well in the trig section because i'd learned it in A2

conic sections, trig functions, law of sines, all of that shit is actually pretty fun EXCEPT for fucking proofs with the identities

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Posts: 1194

NS is fucking smart.

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you're just stupid

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Posts: 4561

NS isn't the place to go from your trig homework, if they can't find out what Tan means then you should stay after school for help. You will get a lot more out of it.

or got to wolfram alpha

http://www.wolframalpha.com/

or got to wolfram alpha

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