FIS Official Tells Pros At Contest "You Don't Do Anything"
Mar 17th 2017Good to see that FIS really care about the skiers.
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DayMan The referenced post has been removed.Yeahh I'm in calc... there's gotta be someone on this website who can help me. This is literally the only thing I'm having trouble in that class with right now, and I have a test tomorrow, so I gotta get this figured out
babumba This might be a repost, but I couldn't find anything similar. Post any problems you are having trouble with here, and if this thread works like it is supposed to, someone else will help you with it. I'll go ahead and start this off:List you out what you know x and y have to equal and guess and check from there? The imaginary answer will be another struggle. I'm in hon. pre calc wbu?
Create a third degree polynomial that has roots at -2 and 6i and goes through the point (0,4). Write your final answer in standard form.
I honestly don't even know where to start on this one..
kamesjelly This might be a repost, but I couldn't find anything similar. Post any problems you are having trouble with here, and if this thread works like it is supposed to, someone else will help you with it. I'll go ahead and start this off:pretty sure you would also need -6i as a root as well. As a math teacher I will give you a little help but not the whole answer. The expresseion below should look familiar and a great place to start.
Create a third degree polynomial that has roots at -2 and 6i and goes through the point (0,4). Write your final answer in standard form.
I honestly don't even know where to start on this one..
DayMan pretty sure you would also need -6i as a root as well. As a math teacher I will give you a little help but not the whole answer. The expresseion below should look familiar and a great place to start.(x+2)(x-6i)(x+6i)Yeah I figured you could just assume that since it's a complex root it has an opposite conjugate, as does every other complex root. Anyway, so when I get to that, should I try to separate the 6i into root[-6] or i * root[6]? Because I feel like trying to FOIL all that out with those imaginaries in there is going to be messy, and it seems like there should be a cleaner, better way to do it. But hey, what do I know, you're the teacher.
kamesjelly Yeah I figured you could just assume that since it's a complex root it has an opposite conjugate, as does every other complex root. Anyway, so when I get to that, should I try to separate the 6i into root[-6] or i * root[6]? Because I feel like trying to FOIL all that out with those imaginaries in there is going to be messy, and it seems like there should be a cleaner, better way to do it. But hey, what do I know, you're the teacher.actually foiling complex conjugates is one of my favorite lessons to teach!
DayMan actually foiling complex conjugates is one of my favorite lessons to teach! The thing you have to remember is that i is equal to sqrt(-1) then i^2 is equal to -1. When we foil (x+6i)(x-6i) we receive F x^2 O 6ix I -6ix L 36i^2 well that simplifies down to x^2+36i^2 which turns into (using the fact that i^2=-1) x^2-36 pretty slick right? Then you just multiply it by your other binomial. I am still a little stumped at the whole goes through (0,4) part though right now....Holy shit you just explained that better than my math teacher could in an entire class. This lady has been teaching way too long, and even after countless complaints from students that she sucks at teaching, due to teacher tenure, she can't get fired.
kamesjelly Holy shit you just explained that better than my math teacher could in an entire class. This lady has been teaching way too long, and even after countless complaints from students that she sucks at teaching, due to teacher tenure, she can't get fired.Ha ha thanks. Always here to help! Calculus is not my jam, but I teach pre-alg to pre-calc.
DayMan Ha ha thanks. Always here to help! Calculus is not my jam, but I teach pre-alg to pre-calc.Shweet thank you I'll have to keep that in mind next time I need help.. Turns out that is right now haha! Would you happen to know very much about the rational root theorem? I'm sorta struggling with the whole concept of it, and how you use it.
cbj ^ give me a problem and I may be able to help you out.integral of dx/(x*ln(x))
Darth.Maul integral of dx/(x*ln(x))Integration by parts is your friend there.
kamesjelly integral of dx/(x*ln(x))do you mean the integral of x*ln(x)?
cbj do you mean the integral of x*ln(x)?no, I mean the integral of (x*ln(x))^-1 dx
Black.Bird no, I mean the integral of (x*ln(x))^-1 dxUse substitution.
kamesjelly no, I mean the integral of (x*ln(x))^-1 dxoh word, alright let's see here....
Darth.Maul Use substitution. u= ln(x) du= (1/x)dx Integral of (1/u)/du is ln(u) Answer: = ln(ln(x)) + CThis guy's got it!
cbj oh word, alright let's see here.... I would first use the rule of negative exponents and rewrite it as 1 x*lnx and then follow integration by parts or substitution. This is actually a very famous integral problem that is a slick trick. I am off for a run. I will check back to see if you still need assistance.Derp. I kept trying to solve it by parts... Fail. Well this question is in the section of my Calculus textbook that is integration by parts, WTF
Darth.Maul Derp. I kept trying to solve it by parts... Fail. Well this question is in the section of my Calculus textbook that is integration by parts, WTFYou can use integration by parts but its a little bit harder.
cbj You can use integration by parts but its a little bit harder.Nope prove it!!
kamesjelly Derp. I kept trying to solve it by parts... Fail. Well this question is in the section of my Calculus textbook that is integration by parts, WTFWell sir, since you are choosing to be an ass. I politely refuse my offer to help you. Have a nice day!
Darth.Maul Nope prove it!!Fine remind me tomorrow. Im tired and its been a semester since ive done calculus or real math. (stats isnt real math which is what im in now)
kamesjelly (stats isnt real math which is what im in now)bhahahahahahahahaha in my 8 years of being on NS this is by far the stupidest thing I have ever read. Stats is used far more often than most math classes by the average joe.
whoa-dere f'(3)=22, and f''(3)=8.might be hard to see, f(3)'s first derivative=22, f(3)'s second derivative=8
MilaKunis what the hell is implicit differentiation?find y^n by implicit differentiation x^4+y^4=1 and x^2-y^2=1 another one find a quadratic equation function f such that f(3)=33, f'(3)=22, and f''(3)=8.For implicit differentation when ever you derive a y value you do what you normally do but then put a Dy/dx in front. For 1 it would be -4x^3/4y^3-= dy/dx
cbj Well sir, since you are choosing to be an ass. I politely refuse my offer to help you. Have a nice day!No, I was accepting it :) My math textbook was just tricking me, I thought I was supposed to use rules I didn't have to
CashmereCat gonna bump this because i'm having trouble. so any ways how would you go about solving log7(343)^2x=x+5 i know there are different properties/rules/formulas but which one do i use? i'm uber confusedRe write as 2x times the log base 7 of 343 to start. After that I'm not 100% sure but probably divide by 2x and solve from there?
Darth.Maul bhahahahahahahahaha in my 8 years of being on NS this is by far the stupidest thing I have ever read. Stats is used far more often than most math classes by the average joe.Someone's meter is busted! Stats is easy as fuck for me compared to Multi Variable Calc though.
burntahoegreen gonna bump this because i'm having trouble. so any ways how would you go about solving log7(343)^2x=x+5 i know there are different properties/rules/formulas but which one do i use? i'm uber confusedhavent done logs in a while but maybe rewrite as: log7(7^3)^2x=x+5
scrambledeggs bhahahahahahahahaha in my 8 years of being on NS this is by far the stupidest thing I have ever read. Stats is used far more often than most math classes by the average joe.english is used far more often than most math classes by the average joe. that doesn't make it "real math" you stupid fuck.
.AR6rider. 2(x-5)+6x\5= 4x-2 7/8+2a\12=3a\4+ 1/3 HELP PLEASE42 to the power of Pi.
*ninja* 42 to the power of Pi.fuk u some1?
Dirac 2(x-5)+6x\5= 4x-2 7/8+2a\12=3a\4+ 1/3 HELP PLEASEhttp://www.wolframalpha.com/input/?i=2%28x-5%29%2B6x%5C5%3D+4x-2
Good to see that FIS really care about the skiers.
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