question is, with the given zeros find the fifth degree equation,

-2i, √3, 1 (negative 2 eye, square root of three, and one)

+k for serious answers

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Posts: 1632

question is, with the given zeros find the fifth degree equation,

-2i, √3, 1 (negative 2 eye, square root of three, and one)

+k for serious answers

-2i, √3, 1 (negative 2 eye, square root of three, and one)

+k for serious answers

"You don't wanna be a boner when you land" - LJ

Posts: 511

id help but i forget it all, you might need to know that another zero is positive 2i

"I know a kid who took two weeds and he OD'd"-God

"tell your parents that your on jupiter and that you'll talk to them later"-raspberry.

"You should try crack! it's fairly cheap and really easy to make! Plus its highly addictive. So you'll have a raging drug addiction in no time!"-mackcamp

"tell your parents that your on jupiter and that you'll talk to them later"-raspberry.

"You should try crack! it's fairly cheap and really easy to make! Plus its highly addictive. So you'll have a raging drug addiction in no time!"-mackcamp

Posts: 1898

the zeroes are the roots of the equation, or the numbers you find when the equation is factored

(x^2+2)(x^2-3)(x-1)

i don't know if the teacher wants factored form, or standard form. If they want standard form, just multiply that out so it looks like:

ax^5+bx^4+cx^3+dx^2+ex+f=0

--------------------------

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According to matt, the bunnies will kill me

you aint me lil bitch. only me could be me.---

Posts: 1632

thanks for trying, still don't get it tho, i've been struggling with this course since the beginning of the semester +k tho

"You don't wanna be a boner when you land" - LJ

Posts: 2315

by zeros i assume you mean roots so... (r-1)(r - sqrt3) then you cant just have a -2i....it should be like 0 plus/minus 2i (real and imaginary part)

but even with those 4 roots its would be a 4th degree polynomial, unless zero is a root where r (in this case) could be factored out of the equation

but even with those 4 roots its would be a 4th degree polynomial, unless zero is a root where r (in this case) could be factored out of the equation

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mike_nickpros

mike_nickpros

Posts: 511

this op i remember now hes got it exactly

"I know a kid who took two weeds and he OD'd"-God

"tell your parents that your on jupiter and that you'll talk to them later"-raspberry.

"You should try crack! it's fairly cheap and really easy to make! Plus its highly addictive. So you'll have a raging drug addiction in no time!"-mackcamp

"tell your parents that your on jupiter and that you'll talk to them later"-raspberry.

"You should try crack! it's fairly cheap and really easy to make! Plus its highly addictive. So you'll have a raging drug addiction in no time!"-mackcamp

Posts: 1632

ok i get it to an extent, so i get the x^2 - 3, that gives u √3, and x-1 gives you 1, but, how do you get the negative 2i, is √-2 = to 2i?

"You don't wanna be a boner when you land" - LJ

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yes.

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i love take home tests, bastard. Lrn2wolfram alpha

Posts: 210

This!

Posts: 1632

sorry, i'd rather ask a question and learn then hand in something with no answer. and what? lrn2wolfram alpha, learn to work from a lpha? no entiendo

"You don't wanna be a boner when you land" - LJ

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wolframalpha.com is an amazing tool.

Posts: 248

This is a really weird question. If -2i is a zero, then +2i also has to be a zero. Also, in order to make it a fifth order polynomial, you're going to have to have a double root. How are you supposed to choose between 1, and root3 as your double root?

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