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This physics problem angers me, help appreciated

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ski93
Posts: 1279 - Karma: 83
Two horizontal parallel plates, 1.2X10^2 m apart, are connected to a DC power supply. The electric field between the plates is 1.7X10^5 V/m. A sphere of mass 3.0X10^-15 with a positive charge of 2.6X10^-12 is injected into the region between the plates, with an initial speed of 3.3X10^3 m/s. It accelerates toward the negative plate. Determine the distance the positive charge moves toward the negative plate after 6.0X10^-6 s have elapsed. Gravitational effects may be ignored in this case.


The answer is 2.7X10^-3 m **apparently you don't need to use calculus to solve this.
Oct 4 2010 11:10PM
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RudyGarmisch
Posts: 25443 - Karma: 13,844
This thread is now about Julia Roberts.

Click for larger image
Oct 4 2010 11:13PM
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ski93
Posts: 1279 - Karma: 83
seriously, this problem is garbage. I just might do that pretty soon lol
Oct 4 2010 11:13PM
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vandersteeze
Posts: 2650 - Karma: 1,511
Use electric field and charge of particle to determine force, forget the equation. Then use that force and the mass of the particle to determine acceleration with F=m*a then use the formula x = x0 + vt + 1/2at^2
Oct 4 2010 11:15PM
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vandersteeze
Posts: 2650 - Karma: 1,511
Oh my bad seems i was off topic
Oct 4 2010 11:16PM
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RudyGarmisch
Posts: 25443 - Karma: 13,844
That thing in the middle of her face, kinda near the bottom, what is it? Its like an expanse so vast that it would tax the greatest imagination and stretch the physical boundaries of our known universe.
Oct 4 2010 11:16PM
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FerrisBueller
Posts: 8280 - Karma: 5,173
use x = x0 + vt + 1/2at^2

and f=ma

while keeping a constant.
Oct 4 2010 11:23PM
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ski93
Posts: 1279 - Karma: 83
for some reason i get the right answer by solving for acceleration and plugging that into the 1/2at^2. Why do i not even need the initial velocity??
Oct 4 2010 11:28PM
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vandersteeze
Posts: 2650 - Karma: 1,511
Because there is none
Oct 4 2010 11:32PM
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ski93
Posts: 1279 - Karma: 83
it's 3.3X10^3 m/s
Oct 4 2010 11:33PM
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vandersteeze
Posts: 2650 - Karma: 1,511
lol im blind. Well i have no idea then
Oct 4 2010 11:37PM
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jeff3617
Posts: 208 - Karma: 102
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Oct 4 2010 11:41PM
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Phormat
Posts: 774 - Karma: 20
I haven't taken physics since freshman year, but think you may need to use Coulomb's Law to find the interacting force between the electric charges. Then plug it into the displacement equation. Something like that...
Oct 4 2010 11:47PM
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Gnarshred
Posts: 5670 - Karma: 18
PEi + KEi = PEf + KEf
Oct 4 2010 11:51PM
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Meases_Pieces
Posts: 1292 - Karma: 246
this equation will help you

( Click for larger image + IA) + ( Click for larger image /3) +S X Click for larger image = Click for larger image
Oct 4 2010 11:58PM
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FerrisBueller
Posts: 8280 - Karma: 5,173
is the object at rest? maybe you dont need it because there is another force acting on it counteracting it. but otherwise idk.
Oct 23 2010 12:49PM
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chapz
Posts: 10182 - Karma: 66
i dont remember anything about dc but im pretty sure there is one or maybe two equations that you should know by now that will let you solve this... no calculus needed.
Oct 23 2010 12:54PM
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thesheik
Posts: 1488 - Karma: 18
.
Oct 23 2010 1:24PM
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Sheets-mmm
Posts: 392 - Karma: 42
dropped the fuck out of physics real real quick
Oct 23 2010 2:12PM
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