What is the pH of a solution that is prepared by dissolving 9.24 grams of salicylic acid (138.12 g/mol) and 7.03 grams of sodium salicylate (160.10 g/mol) in water and diluting to 500 mL. The Ka for salicylic acid is 1.05×10-3.
Can anyone help me solve this?
Your not drunk if you can lie on the floor without holding on
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